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is a city in Jackson County, West Virginia, United States, along the Ohio River. The population was 4,031 at the 2000 census.
Ravenswood is located at (38.952922, -81.761357), along the Ohio River at the mouth of Sandy Creek.
According to the United States Census Bureau, the city has a total area of 1.9 square miles (4.8 km²), of which, 1.8 square miles (4.8 km²) of it is land and 0.04 square miles (0.1 km²) of it (1.60%) is water.